Sandcrete blocks are very popular construction materials for the construction of walls in buildings. They can serve as load-bearing elements or as mere partition panels. There are different types and sizes of sandcrete blocks that are employed in building construction. The size of the block (dimensions) can be a factor in determining the number of blocks required to successfully complete a building.

In order to properly know the cost of constructing a building, it is very important to know the number of blocks that will be able to complete the building. The number of blocks required to construct a building is largely dependent on the type of block, size of the building, area of walls to be built, etc.

In this article, we are going to present a very simple approach to determining the number of blocks required to complete a three-bedroom flat. The floor plan of a three-bedroom flat is shown below, which can comfortably sit on a plot of land of 450 m^{2}. The building consists of a sitting room, three bedrooms (all en-suite), a visitorâ€™s toilet, a dining, a kitchen, a store, and sit-out areas. It is required to estimate the quantity of 6 inches blocks (without holes) required to complete the project.

The data from the building is as shown below;

**DOORS**

Door type 1 (D1) = 1 number (Dimension = 2100 Ã— 1200)

Door type 2 (D2) = 6 numbers (Dimension = 2100 Ã— 900)

Door type 3 (D3) = 4 numbers (Dimension = 2100 Ã— 700)

**WINDOWS**

Window Type 1 (W1) = 12 numbers (Dimension = 1200 Ã— 1200)

Window Type 2 (W2) = 4 numbers (Dimension = 600 Ã— 600)

Storey height (height of the building from floor to ceiling) = 3000 mm

Foundation details of the bungalow are given below.

A section through the wall of the building is given below;

We are going to carry out the calculation in three main phases of construction of bungalow which are;

- Foundation to DPC
- DPC to lintel level, and
- Lintel level to overhead level.

**Estimation of the** **number blocks**

The simplest approach is to estimate the number of blocks required in a metre square of wall.

The planar dimensions of a standard block in Nigeria is (450mm Ã— 225mm).

The planar area of 1 block = (0.225 Ã— 0.45) = 0.10125 m^{2}

Therefore one metre square of a wall will contain;

1/0.10125 = 9.876

Therefore, one metre square of wall will contain approximately 10 blocks.

**PHASE 1: FOUNDATION TO DPC**

At this stage, the total length of the walls of the building and the height of the walls at the substructure level are considered. There are no openings, and the entire foundation excavation length is considered. For the building we are considering, the foundation layout is as shown below;

Using any method of your choice, you can calculate the total length of the walls at the foundation level.

This is approximately equal to 100256 mm = 100.256m from my calculations.

The height of the wall from foundation to DPC (ignoring thickness of mortar) as shown in Figure 3 = 900mm = 0.9m

Therefore, the total area of wall = 100.256m Ã— Â 0.9m = 90.2304m^{2}

If 10 blocks are required for 1m2 of a wall, therefore (10 Ã— 90.2304) = 903 blocks is required for 90.2304m^{2} of wall.

The number of blocks required to raise the building from foundation to DPC = 903 blocks (disregarding damages/waste).

**PHASE 2: DPC TO LINTEL LEVEL**

In this phase, we will consider the effects of openings in the buildings which includes the doors, windows, and other openings as specified in the drawing. These openings are seen in the verandah areas and some of the internal spaces in the building. The same process of calculating the total length of walls is also adopted, after which we minus the area of the openings.

This process is shown below;

Total Length of walls (excluding areas with no walls like verandahs) = 87420 mm = 87.42m

Height of wall = 2100 = 2.1m

Therefore area of wall = (87.42 Ã— 2.1) = 183.582 m^{2}

Total area of all doors from building data = 19.74 m^{2}

Total area of all windows from building data = 18.72 m^{2}^{}Therefore the net area of walls = 183.582 m^{2} â€“ 19.74 m^{2} â€“ 18.72 m^{2} = 145.122 m^{2}^{}Hence, the total number of blocks required to take the building from DPC to lintel level = 145.122 Ã— 10 = 1451.22 = 1452 blocks (disregarding wastes)

**PHASE 3: LINTEL LEVEL TO OVERHEAD LEVEL**

Here, we are going to assume that the building will be chained at the lintel level (this means that the entire level of the building will be cast and reinforced with steel at the lintel level. This offers the advantage of helping the building behave as a unit, and helps in reducing cracking in the building).

Obviously, the length of the wall in this case will not consider openings, so we are going to make use of 100.256m as calculated from the foundation level.

Hence, the length of walls = 100.256m

Height of wall = 675mm = 0.675m

Total area of walls = (100.256 Ã— 0.675) = 67.6728 m^{2}^{}Hence, the total number of blocks required to take the building from the lintel level to the roof level = 67.6728 Ã— 10 = 676.728 = 677 blocks.

**Ultimately, the total number of blocks required to complete the construction of a three-bedrooms flat = 903 + 1452 + 677 = 3032 blocks (disregarding wastage).**

To consider wastage, you can make a 20% increase, so that the number of blocks to be moulded or bought = 1.2 Ã— 3032 = 3638 blocks. However, when you are moulding and can guarantee the quality of blocks to be moulded, 10% increase will be satisfactory for the job.

* READ ALSO IN THIS BLOG;Â *

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Can this design fit into a half plot with enough parking space.

Can this design fit into a half plot with enough parking space.

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