Structville daily questions
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Today’s Question
What is the vertical support reaction at point B of the frame?
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Sum of Moment respect point (A)= By x 5m + 1.0 x 14m = 0 then By = -1.0 x 14 / 5 = – 2.8kN = (-14/5) or if you look at the first triangular bending moment from A to B which is equal to 9.0kNm and divide it for the lever arm which is 5m it is possible to find the reaction Ay = 1.8kN then for the equilibrium of the vertical forces let's say: Ay=1.8kN + By + X2=1.0kn = 0 then By= -2.8 or (-14/5), hence B) is correct.
B) -14/5
Total Reaction, Ay + By = – 1 kN (let's say Equation 1)
Taking moment about B,
Ay x 5 = 1 x 9
Ay = 9/5 kN
Apply the value of Ay in Equation 1, we have
By = -1 – (9/5) = -14/5 kN
B) -14/5
MOMENT ABOUT POINT B
5*Ay=9
Ay=9/5
sum of vertical forces =0
Ay+By+1=0
By=-1-Ay
=-1-9/5
=-14/5
(B) -14/5
A) -9/5
B
By = ((Mab-Mba)/Lab) + ((Mcb-Mbc)/Lbc))
= ((0-9)/5)) + ((5-9)/4)
=-9/5 + -1
=-9/5+-5/5
=-14/5
A) 9/5
-14/5
-14/5
If you calculate moment from Point A you get he equation B*5 + (1)*14=0
And then you get B=-14/5